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(x^2+5x+5)/( x^2+5x+6)-(x^2+8x+14)/(x^2+8x+15) 数学分式运算
人气:479 ℃ 时间:2020-04-04 06:47:48
解答
前半截=1-(1/X²+5X+6)=1-1/(X+2)(X+3)
后半截=1-(1/X²+8X+15)=1-1/(X+5)(X+3)
前-后
=1/(X+5)(X+3)-1/(X+2)(X+3)
=[(X+2)-(X+5)]/(X+2)(X+3)(X+5)
=-3/(X+2)(X+3)(X+5)
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