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分解因式x2-y2-3x-3y=______.
人气:117 ℃ 时间:2020-01-26 07:31:52
解答
x2-y2-3x-3y
=(x2-y2)-(3x+3y)
=(x-y)(x+y)-3(x+y)
=(x+y)(x-y-3).
故答案为:(x+y)(x-y-3).
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