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函数y=cos^2x-2sinxcosx-sin^2x的值域是多少
人气:499 ℃ 时间:2019-08-18 14:40:13
解答
y=cos^2x-2sinxcosx-sin^2x
=cos2x-sin2x
=√2(sinπ/4cos2x-cosπ/4sin2x)
=√2(-2x+π/4)
所以:函数y=cos^2x-2sinxcosx-sin^2x的值域是[-√2,√2]
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