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数学
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已知函数y=cos²x-sin²x+2sinxcosx,求函数值域
人气:203 ℃ 时间:2019-08-18 12:35:58
解答
y=cos²x-sin²x+2sinxcosx
=cos2x+sin2x
=√2 sin(2x+π/4)
所以
值域为【-√2 ,√2 】
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