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(3a²-4a+5)(3a²+4a-5)-a²(9a²-16)
人气:196 ℃ 时间:2020-01-14 14:26:42
解答
(3a²-4a+5)(3a²+4a-5)-a²(9a²-16)=[3a²-(4a-5)][3a²+(4a-5)]-a²(9a²-16)=9a^4-(4a-5)²-9a^4+16a²=16a²-(4a-5)²=(4a+4a-5)(4a-4a+5)=5(8a-5)=40a...
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