设x∈[-1,0]则-x∈[0,1]又f（x）是偶函数；∴f（-x）=f（x）又f（x）的周期为2∴f（-x）=f（-x+2）∴f（x）=f（-x+2）又-x∈[0,1],-x+2∈[2,3]又x∈[2,3]时有：f（x）=x∴f（-x+2）=-x+2∴f（x）=f（-x+2）=-x+2∴x...