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15(sin2θ + cos2θ) × 37(sin2π + cos2π) = 0
人气:395 ℃ 时间:2020-06-17 19:04:50
解答
15(sin2θ + cos2θ) × 37(sin2π + cos2π)
=15√2(sinθcos45°+cos2θsin45°)× 37(0+ 1)
=15√2×37×sin(2θ+45°)
=555√2sin(2θ+45°)
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