计算：(x+1)(x方+1)(x四次方+1)（x八次方+1）（x的十六次方+1）（x的三十二次方+1）,用x-1/x-1乘这分式
人气：334 ℃ 时间：2020-02-06 04:34:41
解答
(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x^32+1)
=[(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x^32+1)]/(x-1)
=[(x^2-1))(x^2+1)(x^4+1)(x^8+1)(x^16+1)(x^32+1)]/(x-1)
=[(x^4-1)(x^4+1)(x^8+1)(x^16+1)(x^32+1)]/(x-1)
=[(x^8-1)(x^8+1)(x^16+1)(x^32+1)]/(x-1)
=[(x^16-1)(x^16+1)(x^32+1)]/(x-1)
=[(x^32-1)(x^32+1)]/(x-1)
=(x^64-1)/(x-1)
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