f(x)=sin(x+π/6)+sin(x-π/6)+cosx+a=sinx*cos(π/6)+cosx*sin(π/6)+sinx*cos(π/6)-cosx*sin(π/6)+cosx+a=（√3）sinx+cosx+a=2sin(x+π/3)+a所以T=2π/1=2π注：a*sin(x)+b*cos(x)=(√a^2+b^2)sin(x+y)(tan...