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计算:-1/2+cos^2(7/8π) 2sin^2(3/4π)-1
人气:318 ℃ 时间:2020-04-10 15:19:12
解答
-1/2+cos^2(7/8π)
=1/2*[2cos^2(7/8π)-1]
=1/2*cos(7/4π)
=1/2*cos(1/4π)
=√2/4
2sin^2(3/4π)-1
=-[1-2sin^2(3/4π)]
=-cos(3/2π)
=0
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