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求助两道初二的二次根式题!
x^-2√2 x-3=?

(1-m)√1/m-1=?
人气:350 ℃ 时间:2020-10-02 03:48:32
解答
x^-2√2 x-3
=x^-2√2 x+2-5
=(x-√2 )^-5
=(x-√2+√5)(x-√2-√5)
(1-m)√1/m-1
=√1/m-√m^/m-1
=1/√m-√m-1
=1/√m-m/√m-√m/√m
=(1-m-√m)/√m
后面的自己算
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