∴(y2-y1)(x-1)=(x2-x1)(y-2),①
由
x12 |
16 |
y12 |
9 |
x22 |
16 |
y22 |
9 |
(x1−x2) (x1+x2) |
16 |
(y1−y2) (y1+y2) |
9 |
又x1+x2=2x,y1+y2=2y,
∴
2x(x1−x2) |
16 |
2y(y1−y2) |
9 |
由①②可得:9x2+16y2-9x-32y=0,③
当点M与点P重合时,点M坐标为(1,2)适合方程③,
∴弦中点的轨迹方程为:9x2+16y2-9x-32y=0.
x2 |
16 |
y2 |
9 |
x12 |
16 |
y12 |
9 |
x22 |
16 |
y22 |
9 |
(x1−x2) (x1+x2) |
16 |
(y1−y2) (y1+y2) |
9 |
2x(x1−x2) |
16 |
2y(y1−y2) |
9 |