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(Log2)的三次方+(Log5)的三次方+3*lg2*lg5=?
人气:129 ℃ 时间:2019-11-22 13:50:30
解答
(log2)^3+(log5)^3+3lg2lg5=(log2+log5)((log2)^2-log2log5+(log5)^2)+3log2log5=log(2*5)((log2)^2+2log2log5+(log5)^2-3log2log5)+3log2log5=log10((log2+log5)^2-3log2log5)+3log2log5=1*((log10)^2-3log2log5)+3...
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