已知x²-5x-2006=0,求代数式（x-2）³-（x-1）²+1/x-2的值
人气：105 ℃ 时间：2019-11-04 03:25:42
解答
x^2-5x-2006=0x^2-5x = 2006[(x-2)^3-(x-1)^2+1]/(x-2)=(x-2)^2+[-(x-1)^2+1]/(x-2)=(x-2)^2+[-x^2+2x-1+1]/(x-2)=(x^2-4x+4) - x(x-2)/(x-2)=x^2-4x+4- x=x^2-5x+4=2006+4=2010
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