f(x)=cos^2x+√3/2sin2x,=(1+cos2x)/2+√3/2 sin2x=(√3/2)sin2x+(1/2)cos2x+1/2=sin2x*cos(π/6)+cos2x*sin(π/6)+1/2=sin(2x+π/6)+1/2(1)最小正周期为T=2π/2=π(2) 增区间2kπ-π/2≤2x+π/6≤2kπ+π/22kπ-2π...若f(C)=3/2 c=1 a=根号3求角A的值你能采纳了再求助吗？不用你增加财富。