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数学
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8y^3+sin2y+x^3+sinx=0求Cos(x+2y)
人气:479 ℃ 时间:2020-07-07 14:17:34
解答
令f(t)=t^3+sint,f(t)为奇函数,f`(t)=3t^2+cost>0(这一点需要证明,或求出f`(t)最小值.简要证明在最后),f(t)单调f(2y)+f(x)=0;f(2y)=-f(x)=f(-x)2y=-x;cos(x+2y)=cos0=1下面证明g(t)=3t^2+cost>0g(t)为偶函数,g(0)=1>...
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