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若m/(x+4)-n/(x-4)=6x/(x^2-16),求mn的值
人气:187 ℃ 时间:2020-03-26 22:03:43
解答
m/(x+4)-n/(x-4)
=[m(x-4)-n(x+4)]/(x^2-16)
=[(m-n)x-4(m+n)]/(x^2-16)
m-n=6m+n=0
解得:
m=3 n=-3
mn=3×(-3)=-9
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