题目是否出错?应该是“求证：BE=AE+CF吧”证：延长DC至G,使CG=AE,连接BG∵正方形ABCD中∴AB=BC（正方形各边相等）∴∠A=∠BCF=90°（正方形各角相等且为90°）∴∠A=∠BCG=90°在△BAE与△BCG中BA=BC∠A=∠BCGAE=CG...