y=-sin2xy=-sin2x的单调递增区间为f(x)=sin2x的单调递减区间所以,2kπ+π/2≤2x≤2kπ+3π/2解得,kπ+π/4≤x≤kπ+3π/4（k为整数）所以,y=-sin2x 的单调递增区间为[kπ+π/4,kπ+3π/4]（k为整数）y=sin(π/3-2x）...