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limx→0 ln(2-x^2)-ln2)/cosx-1的极限
人气:185 ℃ 时间:2020-05-04 18:52:30
解答
limx→0 ln(2-x^2)-ln2)/cosx-1
=lim(x→0) ln(2-x^2)-ln2)/(x^2/2)
=lim(x→0) ln[(2-x^2)/2]/(x^2/2)
=lim(x→0) ln(1-x^2/2)/(x^2/2)
=lim(x→0) (-x^2/2)/(x^2/2)
=-1
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