(5/2-k)x^2+(k-3)x+1/2=0(5/2-k)x^2-(3-k)x+1/2=0(5/2-k)x^2-(5/2-k+1/2)x+1/2=0(5/2-k)x(x-1)-1/2(x-1)=0(x-1)[(5/2-k)x-1/2]=0x-1=0,(5/2-k)x-1/2=0所以若k=5/2,则x=1若k≠5/2,则x=1x=1/(5-2k)所以k=5/2,交点(1,0)...