f( x)=-√3sin²x+sinxcosx=-(√3/2)(1-cos2x)+(1/2) sin2x=√3/2 cos2x +1/2 sin2x - √3/2=sin(2x+π/3) - √3/2f(兀/6)=sin2π/3 - √3/2=√3/2-√3/2=0周期T=2π/2 =π当sin(2x+π/3)=1时 f(x)最大值为1- √...