一.(tanβ - tanα)/(1 - tanβ * tanα) = -2 ∵tanα = 1/3 ∴ (tanβ - 1/3)/(1 - tanβ * 1/3) = -2 tanβ - 1/3 = -2(1 - 1/3 * tanβ)3tanβ - 1 = -6 + 2tanβ)解得tanβ=5 二.∵α∈（π/2,π） cosα =- 1/...