> 数学 >
(sina+sinb)^2+(cosa+cosb)^2=?
A.(COS(a-b)/2)^2
B.4(COS(a-b)/2)^2
C..(sin(a-b)/2)^2
人气:491 ℃ 时间:2020-02-26 02:36:24
解答
(sina+sinb)^2+(cosa+cosb)^2
=sin²a+2sina*sinb+sin²b+cos²a+2cosa*cosb+cos²b
=2+2(sina*sinb+cosa*cosb)
=2+2cos(a-b)
推荐
猜你喜欢
© 2024 79432.Com All Rights Reserved.
电脑版|手机版