应该是4y^2+4y+1+|x-1|=0
(2y+1)²+|x-1|=0
所以2y+1=0,x-1=0
x=1,y=-1/2
原式=(x²-4xy+4y²-4x²+y²+3x²+2xy-y²)/2
=(-2xy+4y²)/2
=-xy+2y²
=1/2+1
=3/2