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函数x=2根号3sinxcosx+2cos平方x-1  x属于r    函数x的单调递减  区间
人气:243 ℃ 时间:2019-08-21 21:10:54
解答
f(x) = 2√3sinxcosx + 2cos^2x-1
= √3sin2x + cos2x
= 2(sin2xcosπ/6+cos2xsinπ/6)
= 2sin(2x+π/6)
2x+π/6 ∈(2kπ+π/2,2kπ+3π/2)时,单调减
∴单调递减区间(kπ+π/6,kπ+2π/3)
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