=sin(π/4-3x)*cos(π/3-3x)-sin[π/2-(π/6+3x)]*cos[π/2-(π/4+3x)]=sin(π/4-3x)*cos(π/3-3x)-sin(π/3-3x)*cos(π/4-3x)由正弦函数两角和差公式得=sin[(π/4-3x)-(π/3-3x)]=sin(-π/12）= -sin(π/12）= -√{...