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[log6(底)3(真)]2(方)+log6(底)18(真)·log6(底)2(真)
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人气:223 ℃ 时间:2020-03-27 02:49:57
解答
[log6(3)]^2+[log6(18)][log6(2)]
=[log6(3)]^2+[log6(3^2*2)][log6(2)]
=[log6(3)]^2+[2log6(3)+log6(2)][log6(2)]
=[log6(3)]^2+2[log6(3)][log6(2)]+[log6(2)]^2
=[log6(3)+log6(2)]^2
=[log6(2*3)]^2
=1
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