1.雷达可用于飞机导航,也可用来监测飞机的飞行.假设某时刻雷达向飞机发射电磁波,电磁波遇到飞机后反射,又被雷达接收,两个过程共用了5.24*10^-5秒,已知电磁波的传播速度为3.0*10^8m/秒,则该时刻飞机与雷达站的距离是多少米?
2.已知2^x=a,3^x=b,求6^x.
3.计算:3x^3-(3x)^2=
人气:420 ℃ 时间:2020-04-27 11:35:14
解答
(1) 3.0×10^8×5.24×10^-5÷2=7.86×10^3(m)
(2)6^x=(3*2)^x=3^x*2^x=ab
(3)3x^3-(3x)^2=3x^2(x-3)
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