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(1+tanα+cotα)/(1+tan^2α+tanα)-cotα/(1+tan^2α)=sinα乘cosα
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人气:456 ℃ 时间:2020-06-09 18:42:44
解答
(1+tanα+cotα)/(1+tan^2α+tanα)-cotα/(1+tan^2α)=cotα(tanα+tan^2α+1)/(1+tan^2α+tanα)-cotα/(1+tan^2α)=cotα(1-1/(1+tan^2α))=cotα*tan^2α/(1+tan^2α)=tanα/(1+tan^2a)=sinα/cosα*(1+sin^2α...
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