=∫(-1,1)[xln(1+x^2)dx+∫(-1,1)πdx
=1/2∫(-1,1)ln(1+x^2)d(1+x^2)+πx|(-1,1)
=1/2*1/(1+x^2)|(-1,1)+[π-(-π)]
=1/2[1/(1+1^2)-1/(1+(-1)^2)]+2π
=1/2(1/2-1/2)+2π
=2π