(1)函数f(x)=ax^3+cx(a>0)在X1,X2处分别取得极值则得,f(x1)'=0,f(x2)'=0f(x)'=3ax^2+c则得3a(x1)^2+c=0,3a(x2)^2+c=o两式相减得,3a(x1^2-x2^2)=0,3a(x1-x2)(x1+x2)=0x1-x2的绝对值为2,a>0,则得x1+x2=0,又|x1-x2|=2,...