∫(1-1/x)^2 dx
=∫(1-2/x+1/x^2)dx
=x-2lnx-1/x+C
∫[(3x)^2+5]/x^3 dx
=∫(9x^2+5)/x^3dx
=∫(9/x+5*x^(-3))dx
=9lnx-5/(2x^2)+C