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已知x>1 求(x^2-x+3)/(x-1)最小值(用均值不等式求)谢谢
人气:416 ℃ 时间:2020-09-08 07:33:19
解答
x>1则x-1>0
原式=(x²-x)/(x-1)+3/(x-1)
=x(x-1)/(x-1)+3/(x-1)
=x+3/(x-1)
=(x-1)+3/(x-1)+1≥2√[(x-1)*3/(x-1)]+1=2√3+1
所以最小值是2√3+1
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