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数学
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求不定积分∫x/(x²+2x+2)dx
人气:344 ℃ 时间:2019-09-17 21:36:19
解答
∫x/(x²+2x+2)dx=1/2*∫(2x+2-2)/(x²+2x+2)dx
=1/2*∫(2x+2)/(x²+2x+2)dx-∫1/(x²+2x+1+1)dx
=1/2ln(x²+2x+2)+arctan(x+1)+C
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