f(x) = √3sin2x-2sin^2x= √3sin2x - (1-cos2x)= √3sin2x + cos2x - 1= 2(sin2xcosπ/6+cos2xsinπ/6) - 1= 2sin(2x+π/6) - 1最小正周期=2π/2=π2x+π/6∈（2kπ-π/2,2kπ+π/2）时单调增,所以单调增区间（kπ-...