y<√﹙2x-1﹚+√﹙1-2x﹚+3／2
∵2x-1≥0,1-2x≥0∴x=1／2∴y<3／2∴2y-3＜0∴﹙4y-6﹚／√（2y-3）²=﹣﹙4y-6﹚／（2y-3）=-2