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若(a+b)^2=10,(a-b)^2=2,求5a^2b^2的值
人气:494 ℃ 时间:2020-03-28 14:27:27
解答
ab
=[(a+b)^2-(a-b)^2]/4
=(10-2)/4
=2

5a^2b^2
=5(ab)^2
=5×2^2
=20
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