f(x)=sin(2x+π/6)-cos(2x+π/3)+2cos²x=根号下3sin2x/2+cos2x/2-cos2x/2+根号下3sin2x/2+2cos²x-1+1=根号下3sin2x+cos2x+1=2(根号下3sin2x/2+cos2x/2)+1=2sin(2x+π/6)+1f(π/12)=2sin(π/3)+1=根号下3+1...