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a+(1/a)=? (x的平方+9x/x的平方+3x)+(x的平方-9/x的平方+6x+9)=?
人气:226 ℃ 时间:2020-01-28 09:21:48
解答
a+1/a
=a²/a+1/a
=(a²+1)/a
(x²+9x)/(x²+3x)+(x²-9)/(x²+6x+9)
=x(x+9)/x(x+3)+(x+3)(x-3)/(x+3)(x+3)
=(x+9)/(x+3)+(x-3)/(x+3)
=(x+9+x-3)/(x+3)
=(2x+6)/(x+3)
=2(x+3)/(x+3)
=2
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