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2分之根号2乘以(1-i)的2008次方等于多少?
人气:131 ℃ 时间:2020-01-31 13:11:16
解答
[√2/2*(1-i)]^2008
={[√2/2*(1-i)]²}^1004
=[1/2(1+i²-2i)]^1004
=[1/2(-2i)]^1004
=[(-i)²]^502
=(1)^502
=1
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