y=x/(√a²-x²),求dy/dx!
人气：112 ℃ 时间：2020-03-13 04:12:14
解答
dy/dx=[x/√(a²-x²)]'
=[√(a²-x²)+x²/√(a²-x²)]/(a²-x²)
=[(a²-x²)+x²]/(a²-x²)^(3/2)
=a²/(a²-x²)^(3/2).
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