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2道因式分解
1:900^2-1800*892+892^2
2:(1-1/2^2)*(1-1/3^2)……(1-1/2005^2)(1-1/2006^2)
要因式分解的...还有过程
人气:310 ℃ 时间:2020-05-14 06:28:17
解答
1:900^2-1800*892+892^2
=900^2-2*900*892+892^2
=(900-892)^2
=8^2
=64;
2:(1-1/2^2)*(1-1/3^2)……(1-1/2005^2)(1-1/2006^2)
=(1-1/2)(1+1/2)(1-1/3)(1+1/3).(1-1/2006)(1+1/2006)
=(1/2)(3/2)(2/3)(4/3).(2005/2006)(2007/2006)
=(1/2)(2007/2006)
=2007/4012.
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