BD和AE较于H,∠AHB60°.证明：∵△ABC和△DEC都是等边三角形∴BC=AC,CD=CE,∠BCA=∠DCE=60°∠BCD=∠ACE=60°+∠ACD∴△BCD全等△ACE∴∠CBD=∠CAE△ABH中：∠AHB=180°-∠BAH-∠ABH= 180°-(∠BAC+∠CAE)-(∠ABC-∠...