设a=2002,原式化为：=(a-3)(a-2)(a-1)(a+1)(a+2)(a+3)+36 =(a^2-1)(a^2-4)(a^2-9)+36 =a^6-(1+4+9)a^4+(4+9+36)a^2-36+36 =a^6-14a^4+49a^2 =a^2(a^4-14a^2+49) =a^2(a-7)^2 =[a(a-7)]^2 所以是完全平方数...