> 数学 >
已知x+y=7,xy=2,求下列各式的值:
(1)2x2+2y2的值;
(2)(x-y)2的值.
人气:409 ℃ 时间:2019-08-18 22:26:30
解答
(1)∵x+y=7,
∴x2+2xy+y2=49,
∵xy=2,
∴x2+2×2+y2=49,
解得x2+y2=45,
∴2x2+2y2的值是90;
(2)∵x2+y2=45,xy=2,
∴(x-y)2=x2-2xy+y2
=45-2×2,
=41.
故答案为:90,41.
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