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设函数z=x+y/x-y 则dz=?
人气:207 ℃ 时间:2020-02-05 06:21:41
解答
f(x)=z=x+y/x-y
dz=fxdx+fydy=[[(x-y)-(x+y)]/(x-y)^2 ]dx+[[(x-y)+(x+y)]/(x-y)^2]dy
=-2y/(x-y)^2 dx+2x/(x-y)^2 dy
=2/(x-y)^2 (xdy-ydx)
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