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已知函数y=cos2x+sin^2-cosx.求最大值与最小值
人气:219 ℃ 时间:2019-10-19 16:17:21
解答
cos2x=cos^2-sin^2
cos2x+sin^2-cosx
=cos^2-sin^2+sin^2-cosx
=cos^2-cosx
=cos^2-cosx+1/4-1/4
=(cosx-1/2)^2-1/4
-1
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