1-x²-y²+x²y²+4xy=48
x²y²+2xy+1-(x²-2xy+y²)=48
(xy+1)²-(x-y)²=48
令a=xy+1,b=x-y
a²-b²=48
(a+b)(a-b)=48
xy+x-y+1=6
即a+b=6
所以a-b=48÷6=8
即xy+1-x+y=8
所以xy-x+y+1=8