tan(π+a)=-1/3tana=-1/3[sin(π-2a)+cos^2a]/[2cos2a+sin2a+2]=[sin(2a)+cos^2a]/[2cos2a+sin2a+2]=[2sinacosa+cos^2a]/[4cos^2a+2sinacosa]=[2sina+cosa]/[4cosa+2sina]=[2tana+1]/[4+2tana]=(2*(-1/3)+1)/(4+2*(-...